written 6.2 years ago by |
Moment of momentum equation state that "The resulting torque acting on a rotating Fluid is equal to the rate of change of moment of momentum.
let $V_{A} and V_{B}$ are the velocity of nozzle 1 & 2 and $r_{1}$ and $r_{2}$ their respective radius of curvature
Momentum of Fluid at section 1
= $mass \times Velocity= pQ \times Va$
Where Q is the flow rate of liquid
Moment of momentum per second of fluid at section 1 =$(PQV_{A})r_{1}$
Similarly moment of momentum per second of fluid at section 2 =$(PQV_{B})r_{2}$
Rate of change of momentum=$PQV_{B}R_{2}-PQV_{A}r_{1}$
=$PQ(V_{B}r_{2}-V_{A}R_{1})$
According to the moment of momentum principle
Resultant torque=rate of change of motion in momentum Torque T=$PQ(V_{B}r_{2}-V_{A}r_{1})$
this equation is known as moment of momentum equation