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1 kg of air at a pressure of 14 bar occupies 0.6 m3 and from this condition it expands to 1.4 bar according to law PV1.25=C

Find: (i) Change in internal energy (ii) Work done by air Assume Cp = 1.005 KJ/kg K and Cv = 0.718 KJ/kg K

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Given data: Initial pressure = P1 = 14 Bar = 14 x 105 N/m2

Final pressure = P2 = 1.4 Bar = 1.4 x 105 N/m2

Initial volume = V1 = 0.6 m3

Cp = 1.005 kJ/kgK,

Cv = 0.718 kJ/kgK and

Process is PV1.25=C

Air mass m …

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