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Using Boolean Algebra, prove the following
1 Answer
written 6.1 years ago by |
$1) AB+\bar AC+BC$ $=AB+\bar AC+BC(A+\bar A)$ $(A+\bar A=1$, Complementary law)
$=AB+\bar AC+ABC+\bar ABC$
$=AB+ABC+\bar AC+ABC$ (Associative law)
$=AB+\bar AC$ (Absorption law)