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Minimize the expression using Quine Mc-cluskey technique

$$F(A,B,C,D) = \sum M(0,1,2,3,5,7,9,11)$$

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Step 1. Grouping maxterms according to number of 1s

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Step 2. Combining maxterms in group of two

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Step 3. Combining maxterms in group of four

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Interpreting from the table -

$F(A,B,C,D) = \bar A \bar B + \bar A D + \bar B D $

Step 4. Prime Implicant table

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From the prime implicant table, $\bar A \bar B + \bar A D + \bar B D$ are the Essential Prime Implicants.

Hence, the minimized expression will be - $F(A,B,C,D) = \bar A \bar B + \bar A D + \bar B D$

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