Axial flow compressor has a constant axial velocity of 150 m/s and 50% reaction.The mean diameter of the blade ring is 35 cm and speed is 15,000 rpm.The exit angle of the blade is 27deg.

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written 6.5 years ago by

teamques10 ★ 69k

• modified 6.5 years ago

Given:

$V_f = 150\hspace{0.05cm}m/s,\hspace{0.25cm}R_d = 50\hspace{0.05cm}\%\\ D_m = 35\hspace{0.05cm}cm,\hspace{0.25cm}N = 15000\hspace{0.05cm}rpm,\hspace{0.25cm}\alpha = 27^\circ$

To Find: $\alpha_2 = \hspace{0.05cm}?,\hspace{0.25cm}\textit{W.D/kg of air} = \hspace{0.05cm}?$

Solution:

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$\hspace{5cm}V_b = \frac{\pi D_{mean}.N}{60}\\ \hspace{5.5cm}= \frac{\pi\hspace{0.05cm}\times\hspace{0.05cm}0.35\hspace{0.05cm}\times\hspace{0.05cm}15000}{60}\\ \hspace{5.5cm}= 274.75\hspace{0.05cm}m/s\\ \hspace{5cm}\frac{V_b}{V_f} = \tan\beta_1 + \tan\beta_2\\ \hspace{4.5cm}\frac{274.75}{150} = \tan\beta_1 + \tan(27^\circ)\\ \hspace{5cm}\beta_1 = \alpha_2 = 52.898^\circ$

$\textit{W.D/kg of air} = …

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