(8 marks) May-18

Area of steel rod $A_s=\frac{\pi}{4}*15^2=56.25 \pi mm^2$

Area of coppper rod $A-c=\frac{\pi}{4}*(50-40)^2=225\pi mm^2$

Free expansion:

$\delta_{steel}=\alpha_s TL$

$\delta_{copper}=\alpha_c TL$

Let the actual expansion of each component be \delta

$\alpha_c TL \gt\delta\gt \alpha_s TL$

Steel is in tension and copper is in compression. Let $P_s$ and $P_c$ be …