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Write a note on frequency sampling realization of FIR filter.
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We know that,

DFT of h(n) is given by:

H(k)=N1n=0h(n)ej2πknN …………………(1)

From the equation of IDFT we have,

h(n)=1NN1k=0H(k)ej2πknN…………………(2)

By the definition of Z transform we have,

              $H(z)=∑_{n=0}^{N-1}h(n) z^{-n}$…………………(3)

Put the value of h(n) from equation (2) to equation (3), we get

H(z)=N1n=01NN1k=0H(k)ej2πknNzn

H(z)=1NN1k=0H(k)N1n=0ej2πknNzn

Now by sum of finite GP series we have;

We know that, ej2πk=1

H(z)=(1zN)NN1k=0[H(k)(1ej2πkNz1)]

H(z)=(1zN)N[H(0)(1z1)+H(1)(1ej2πNz1)+H(2)(1ej4πNz1)++H(N1)(1e(j2π(N1))Nz1)]

Frequency Sampling Realization;

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