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The first points of 8-point DFT of real valued sequence are{0.25,0.125-j0.3018,0,0.125-j0.0518,0} Find the remaining three points.

written 6.5 years ago by teamques10 ★ 69k

•   modified 5.5 years ago

discrete time signal processing

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written 6.5 years ago by teamques10 ★ 69k

By Symmetry property we have,

$X(k)=X^* (N-k)$

We have

X(0)=0.25

X(1)=0.125-j0.3018

X(2)=0

X(3)=0.125-j0.0518

X(4)=0

$k=5,X(5)=X^* (8-5)$

=$X^* (3)$

=0.125+j0.0518

$k=6,X(6)=X^* (8-6)$

$=X^* (2)$

=0

$k=7,X(7)=X^* (8-7)$

$=X^* (1)$

=0.125+j0.3018

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