0
1.0kviews
Justify DFT as a linear transformation.
1 Answer
written 6.2 years ago by |
If $x_1(n) (\lt-\gt)^{DFT} x_1(k)$ And
$x_2(n) (\lt-\gt)^{DFT} x_2(k)$ Then
$a_1x_1(n) + a_2x_2(n) (\lt-\gt)^{DFT} a_1x_1(k) + a_2x_2(k) $
Proof:- By the definition
x(k) = ∑ x(n) $(W_n)^{Kn}$
here x(n) = $a_1x_1(n)$ + $a_2x_2(n)$
=> X(K) = ∑[$a_1x_1(n)$ + $a_2x_2(n)$]$(W_n)^{Kn}$
X(K) = $a_1X_1(k)$ + $a_2X_2(k)$
Hence proved.