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Find the minimum energy of neutron confined to a nucleus of size of the order of (10)^{-14} m.
written 6.0 years ago by | • modified 4.4 years ago |
Given mass of neutron =$ 1.675×10^{(-27)}$ kg
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written 6.0 years ago by | • modified 4.4 years ago |
Given mass of neutron =$ 1.675×10^{(-27)}$ kg
written 6.0 years ago by |
Given data :- L = $10^{(-14)}$ m
$ Formula :- E_n= n^2 (h^2/(8mL^2 )) …………………….(n = 1,2,3…..)$
$ Solution :- E_n= n^{2} (h^2/(8mL^2 )) = ((6.63 × 10^{(-34)})×(6.63 × 10^{(-34)}))/(8×1.67 ×10^{(-27)}×{(10^{(-14)})}^2 ) …..(n=1)$
$ E_1 = 3.29 × 10^{(-13)}J$
Lower energy$ = 3.29 × 10^{(-13)}J$