Find the minimum energy of neutron confined to a nucleus of size of the order of (10)^{-14} m.

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written 6.5 years ago by

teamques10 ★ 69k

• modified 5.0 years ago

Given mass of neutron = $1.675×10^{(-27)}$ kg

engineering physics

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written 6.5 years ago by

teamques10 ★ 69k

Given data :- L = $10^{(-14)}$ m

$Formula :- E_n= n^2 (h^2/(8mL^2 )) …………………….(n = 1,2,3…..)$

$Solution :- E_n= n^{2} (h^2/(8mL^2 )) = ((6.63 × 10^{(-34)})×(6.63 × 10^{(-34)}))/(8×1.67 ×10^{(-27)}×{(10^{(-14)})}^2 ) …..(n=1)$

$E_1 = 3.29 × 10^{(-13)}J$

Lower energy $= 3.29 × 10^{(-13)}J$

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