Work out the quantity of steel in a 7.0m long S.S beam of size 350*600mm overall. Bottom Bar: 4-12mm diameter straight bars. Anchor bars 2-12mm diameter straight bars, stirrups 10mm diameter @250mm c/c throughout the length of the beam. Clear Cover as 25mm on all sides. Refer fig.

1) Length of bottom bar

L= Length of beam – 2×cover + (2×9×d)

L=7000 – (2×25) + (2×9×12)

L=7166m

2) Length of Anchor bar

L= Length of beam – 2×cover + (2×9×d)

L=7000 – (2×25) + (2×9×12)

L=7166m

3) Length of Stirrups

L= {[2×(depth – 2×cover)]+ [2×(depth – 2×cover)]}× 24d

L = {[2×(600 – 2×25)]+ [2×(350 – 2×25)]}×24×10

L=1940m

No. of Stirrups $=\frac{L-2*cover}{spacing}+1 \\ =\frac{1940-2*50}{250}+1 \\ =8.56m$

Total weight = 61.82kgs = 62kgs (Say)