(*No need of using center line or long wall short wall method for framed structure)
Trapezoidal part of footing
$A1=0.7×0.7=0.49m² \\
A2=0.33*0.33=0.1089m² \\
Am=\frac{A1+A2 }{2}=0.2995 \\
V=\frac{D}{6}[A1+A2+4Am] \
=\frac{0.30}{6}[0.49+0.1089+(4*0.2995)]
=0.089m³$
Rectangular Portion =$0.7×0.7×0.15 =0.0735m³$
Total volume of Foundation
$= 0.089+0.0735=0.1625m³$
f) For roof slab & roof beam
Total area of slab $= (9.49×6.39) + (5.26×(8.46-6.39)) \\
=60.64+10.89=71.53m²$
Depth of Beam for given diagram
=3.0-2.1=0.9m
Total Length of beam =42.6m
Total R.C.C quantity in beam=0.23×0.9×42.61=8.82m³
R.C.C quantity in slab= (Total area of slab–columns–beams)
$=\bigg\{71.52-(0.23*0.23*10) \frac{8.82}{0.9}\bigg\}×0.1 \\
=(71.53-0.529-9.8)×0.1 \\
=6.1m³$