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Implement the following Boolean function using only one 4:1 Mux and few gates
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written 6.6 years ago by | • modified 6.5 years ago |
D0=¯A¯B+A¯B=¯B(A+¯A)
D1=¯A¯B+AB
D2=¯A¯B
D3=¯A¯B+AB