Developed the flexibility method for given cordinate.

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written 6.6 years ago by

teamques10 ★ 69k

• modified 3.2 years ago

Subject:- Structural Analysis II

Title:- Flexibility Method

Difficulty:- Hard

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structural analysis

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written 6.6 years ago by

teamques10 ★ 69k

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Σ $M_A = 0$ ----(M-1)

1 - $V_B$ *5 = 0

$V_B$ = 0.2KN

Σ $F_Y$ = 0

- $V_A$ + 0.2 = 0

$V_A$ = 0.2KN

Σ $M_A = 0$ -----(M-2)

12 - $V_B$ 5 = 0

$V_B$ = 0.4KN

Σ $F_Y$ = 0

$V_A$ - 1 + 0.4 = 0

$V_A$ = 0.6KN …

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