Liquid limit of clay soil 56% plasticity Index 15% i)What state of this material water content of 45%ii)plastic limit of soil iii)Void ratio soil minimum volume reached shrinkage 0.88.Shrinkage G=2.71

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teamques10 ★ 68k

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geotechnical engineering

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written 6.2 years ago by

teamques10 ★ 68k

Given:- $W_{L}$=56%, Ip=15%, W=45%

(i) $I_{c}=\frac{W_{L}-W}{I_{p}} = \frac{56-45}{15}$=0.73

soil is in plastic state and has medium stiff consistency

ii)$W_{p}=w_{L}-I_{p}=56-15$=41%

iii) e=0.88, G=2.71, $W_{s}$=?

$s_{d}=\frac{G\gamma_{w}}{1+e} = \frac{2.71 \times 1}{1+0.88}$=1.44g/c.c

$W_{s}=\frac{s_{w}}{S_{d}}=\frac{1}{G}=\frac{1}{1.44}-\frac{1}{2.71}$=0.325 i.e 32.5%

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