written 6.2 years ago by |
From fig the flow curves for soil A and soil B
From the fig $(w_{L})_{A}$=38%
$(wl)_{B}$=60%
a) $(Ip)_{A}$=38-25=13
$(Ip)_{B}$=60-30=30
soil B has a higher degree of plasticity soils with $IP \gt 17$ are highly plastic and soils with Ip between 7 and 17 are "medium plastic", according to one empirical classification system
b) $(IL)_{A}$=$\frac{W_{N}-W_{P}}{IP}$ = $\frac{40-25}{13}$
$(IL)_{B}=\frac{50-30}{30}$=0.67
soil A with $I_{2}\gt 1$ is in the liquid state of consistency and will, therefore 'flow' like a viscous clurry upon remoulding. soil B with $I_{2}$=0.67 is in the plastic state and will be a better foundation material upon remoulding.
c)soil with WL=60% is more compressible than soil A with wL=38% compressibility is a direct function of the liquid limit
d) From fig, Flow Index, If of soil A=42.0-32.0=10 (Considering water content at 10 and 100 blows) If for soil B=6.26-55.5=71
Since $(IF)/A \gt (If)_{B}$ soil A showed greater loss if shear strength with increase in water content
e) Toughness Index, $I_{t}$ for soil A=$\frac{IP}{IF}=\frac{13}{10}$=1.3
If for soil B=$\frac{Ip}{If}=\frac{30}{71}$=4.22
soil B has a higher shear strength at plastic limit since a soil with higher toughness index possess higher shear strength at plastic limit