0
755views
If WL=51%, Wp=32% Ws=19% Soil specimen shrinks from volume 42.5 cc at wL to 26.8 cc of shrinkage limit.Determine gravity
1 Answer
0
4views

enter image description here

Reduction in volume R=42.5-26.8

=15.7cc

=15.7gm

% reduction in water content =51 to 1g=32% w=\frac{M_{w}}{M_{s}}=0.32

Ms=Mw0.32=15.70.32=49.06gm

Initial Mw in soil sample=0.51 Ms=0.51×49.06

=25.02gm Volume of water initially

Vs=volume of solids=42.5-25.05

=17.478 cc

GMsVs×Pw=49.0617.478×1

=2.806

Please log in to add an answer.