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If WL=51%, Wp=32% Ws=19% Soil specimen shrinks from volume 42.5 cc at wL to 26.8 cc of shrinkage limit.Determine gravity
1 Answer
written 6.6 years ago by |
Reduction in volume R=42.5-26.8
=15.7cc
=15.7gm
% reduction in water content =51 to 1g=32% w=\frac{M_{w}}{M_{s}}=0.32
Ms=Mw0.32=15.70.32=49.06gm
Initial Mw in soil sample=0.51 Ms=0.51×49.06
=25.02gm Volume of water initially
Vs=volume of solids=42.5-25.05
=17.478 cc
GMsVs×Pw=49.0617.478×1
=2.806