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Difference between specific Gravity of solids(G) and specific gravity of soil
1 Answer
written 6.6 years ago by |
1)Embankment:-
e=n1−n=0.31−0.3=0.428
s=w.Ge = 0.15×2.680.428
s= 93.9%
γ=(G+s.e)(1+e)γw
[2.68+0.939+0.42781+0.428]×9.81
=21.17 kN/m3
ac=n(1−s)
=0.3[1-0.939]
ac=0.0183
wt of soil=γ×2000m3
w=17×2000kN
Volume of compacted embankment
v=wv 17×200021.17=1606m3
Volume of compacted embankment is 1606m3