*after reading 3.905 next reading 0.600 is decrease and then increase 1.410
Then 0.600 is entered in FS and 1.410 enter on BS
Staff reading |
chainage |
B.S |
I.S |
F.S |
H.I |
R.L |
Remark |
P |
0 |
1.500 |
|
|
591.6 |
590.100 |
RL of BM |
1 |
15 |
|
1.785 |
|
|
589.815 |
|
2 |
30 |
|
2.490 |
|
|
589.11 |
|
3 |
45 |
|
2.995 |
|
|
588.605 |
|
4 |
60 |
|
3.555 |
|
|
588.045 |
|
5 |
75 |
|
3.905 |
|
|
587.695 |
|
6 |
90 |
1.410 |
|
0.600 |
592.41 |
591 |
CP1 |
7 |
105 |
|
2.510 |
|
|
589.9 |
|
8 |
120 |
|
2.915 |
|
|
589.495 |
|
9 |
135 |
|
3.105 |
|
|
589.305 |
|
10 |
150 |
|
3.995 |
|
|
588.415 |
|
11 |
165 |
1.500 |
|
0.960 |
592.95 |
591.45 |
CP2 |
12 |
180 |
|
1.675 |
|
|
591.275 |
|
13 |
195 |
|
2.410 |
|
|
590.54 |
|
14 |
210 |
|
2.995 |
|
|
589.955 |
|
Q |
225 |
|
|
3.615 |
|
589.335 |
|
|
|
∑B.S = 4.41 |
|
∑F.S = 5.175 |
|
|
|
1. HI=RL of P + BS= 590.100 +1.500= 591.6
2. RL Of point 1= HI – IS of point 1 = 591.6 – 1.785 =598.815
3. RL Of point 2= HI – IS of point 2 = 591.6 – 2.490 =598.11
4. RL Of point 3= HI – IS of point 3 = 591.6 – 2.995 =588.605
5. RL Of point 4= HI – IS of point 4 = 591.6 – 3.555 =588.045
6. RL Of point 5= HI – IS of point 5 = 591.6 – 3.905 =587.695
7. RL Of point 6= HI – FS of point 6 = 591.6 – 0.600 =591
8. Change point= new HI of point 6= RL of point 6 + BS of point 6 = 591 – 1.410=592.41
9. RL Of point 7= HI point 6 – IS of point 7 = 591.6 – 2.510 =589.9
10. RL Of point 8= HI point 6 – IS of point 8 = 591.6 – 2.915 =589.495
11. RL Of point 9= HI point 6 – IS of point 9 = 591.6 – 3.105 =589.305
12. RL Of point 10= HI point 6 – IS of point 10 = 591.6 – 3.995 =588.415
13. RL Of point 11= HI point 6 – FS of point 11 = 591.6 – 0.960 =591.45
14. Change point= new HI of point 11= RL of point 11 + BS of point 11 =591.45– 1.500=592.95
15. RL Of point 12= HI point 11 – IS of point 12 = 592.95– 1.675=591.275
16. RL Of point 13= HI point 11 – IS of point 13 = 592.95– 2.410=590.54
17. RL Of point 12= HI point 11 – IS of point 14 = 592.95– 2.995=589.955
18. RL Of point Q= HI point 11 – FS of point Q = 592.95– 3.615=589.335
Arithmetic check:
∑B.S - ∑F.S = Last RL-First RL
4.41 - 5.175 = 589.335 – 590.100
-0.765 = -0.765
Gradient of PQ = (First RL-last RL) / (Distance PQ) = (590.100-589.335) / 225 = 1 / 294.12
= 1 in 294.12 (falling)