Subject: Structural Analysis II

Topic: Flexibility Method

Difficulty: Medium / High

1)Free Bending moment

• For Span BC at $F=\frac{wl^{2}}{8}=\frac{2\times(6)^{2}}{8}=9kN.m$

• For Span CD at $G=\frac{wl^{2}}{8}=\frac{2\times(8)^{2}}{8}=16kN.m$

2) Free Bending moment diagram

3) Find Reaction at Support:-

Reaction at $B=4+4.94=8.94kN$

Reaction at $C=7.06+9.16=16.23kN$