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primary sewage treatment numerical

Treated waste water is discharged at the rate of 1.5m3/sec into a river of minimum flow of 5m3/sec. The temperature of river flow and waste water flow may be assumed at 25°C.The BOD removal rate constant k1 is 0.12/d, water upstream of the waste water is 200 mg/s and that of the river water upstream of the waste water outfall is 1 mg/l. The efficiency of waste water treatment is 80%. Evaluate

  1. BOD5 at 20°C . if river water receives untreated waste water.
  2. BOD5 at 25°C , if river water receives treated waste water
  3. ultimate BOD of the river water after it receives treated waste water.
1 Answer
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Given:-

Discharge of waste water=Qw=1.5m3/s

Discharge of river=Qr=5m3/s

Temperature=T=25°C

Kd(25°)=k1=0.12/d

Cw=concofBOD5 for untreated waste water

=200 mg/l

Cr=conc.ofBOD5 for river water=1mg/l

  1. conc. ofBOD5 of the mixture if untreated waste water is discharged into the river

C=CwQw+CRQRQw+QR

C=2001.5+151.5+5

C=46.92mg/l

  1. BOD5 of the treated …

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