written 6.7 years ago by
teamques10
★ 69k
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modified 6.7 years ago
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To find horizontal deflection at A, apply fictitious or Dummy force P= 1 KN horizontal towards left.
- Axial force(N) and Bending Moment(M)
Diagram:

Applying C.O.E:
Σ MD=0 (+ve)
−1×3−MD=0
MD=3 KN.m
ΣFy=0(↑+ve)
VD=0
ΣFx=0(→+ve)
−1+HD=0
HD=1 KN
Consider port 'A B' :
BMB=1×1=1 KN
Consider port BC:

Consider port CD:
BMC=1 KN.m
BMD=−3KN.m
2. Deflection at A: (Considering effect of axial forces)
(a) Member AB :(10∘C→30 ∘C)
∴TC=10 + (30−10)2=20∘C
△t=30∘C−10∘C=20∘C
△tn=200.2=100
¯A=12×1×1=0.5m2
¯N=0
(b) Member BC :(10∘C→40 ∘C)
∴TC=10 + (40−10)2=25∘C
△t=40∘C−10∘C=30∘C
△tn=300.2=150
¯A=1×4=4 m2
¯N=1
(c) Member CD :(10∘C→30 ∘C)
∴TC=10 + (30−10)2=20∘C
△t=30∘C−10∘C=20∘C
△tn=200.2=100
¯A=−12×3×3+ 12×1×1=−4 m2
¯N=0