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Deflection of statically Determinate Structures

For the rigid jointed frame subjected to temperature variation as shown in the figure. Determine the horizontal deflection at A.

Assume α = 12 x 10^-6 /c depth of all member as 200 mm. Neglect effect of axial force. enter image description here


Subject: Structural Analysis II

Topic: Deflection caused by temperature changes

Difficulty:Medium

1 Answer
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To find horizontal deflection at A, apply fictitious or Dummy force P= 1 KN horizontal towards left.

  1. Axial force(N) and Bending Moment(M)
    Diagram:

enter image description here

Applying C.O.E:

Σ MD=0 (+ve)
1×3MD=0
MD=3 KN.m
ΣFy=0(+ve)
VD=0
ΣFx=0(+ve)
1+HD=0
HD=1 KN
Consider port 'A B' :
enter image description here BMB=1×1=1 KN

Consider port BC:
enter image description here

Consider port CD: enter image description here BMC=1 KN.m
BMD=3KN.m


2. Deflection at A: (Considering effect of axial forces)

(a) Member AB :(10C30 C)
TC=10 + (3010)2=20C
t=30C10C=20C
tn=200.2=100
¯A=12×1×1=0.5m2
¯N=0


(b) Member BC :(10C40 C)
TC=10 + (4010)2=25C
t=40C10C=30C
tn=300.2=150
¯A=1×4=4 m2
¯N=1


(c) Member CD :(10C30 C)
TC=10 + (3010)2=20C
t=30C10C=20C
tn=200.2=100
¯A=12×3×3+ 12×1×1=4 m2
¯N=0

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