Analyze the following circuit to get voltage gain equation if M2 is twice as wide as that of M1 and Vin1 = Vin2.

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written 6.6 years ago by

hetalgosavi • 1.7k

modified 4.6 years ago by

prashantsaini • 0

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cmos vlsi design

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written 6.6 years ago by

hetalgosavi • 1.7k

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$(\frac{W}{L})_1=2(\frac{W}{L})_2$

$\therefore\,\, I_{D_{2}}=2I_{D_{1}}\,\,\,=\gt\,\,\,g_{m_{2}}=2g_{m_{1}}$

Therefore, small signal voltage is given by,

$|A_v|=\frac{2R_D}{\frac{1}{g_{m_{1}}}+\frac{1}{g_{m_{2}}}}=\frac{2R_D}{\frac{1}{g_{m_{1}}}+\frac{1}{2g_{m_{1}}}}=\frac{2R_D}{\frac{3}{2g_{m_{1}}}}=\frac{4}{3}g_{m_{1}}\,R_D$

$\therefore\,\,\,|A_v|=\frac{4}{3}g_{m_{1}}\,R_D$

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