written 6.6 years ago by | • modified 2.8 years ago |
Subject: CMOS VLSI Design
Topic: CMOS analog building blocks
Difficulty: Medium
written 6.6 years ago by | • modified 2.8 years ago |
Subject: CMOS VLSI Design
Topic: CMOS analog building blocks
Difficulty: Medium
written 6.6 years ago by | • modified 6.6 years ago |
1) n-MOS
(a) Basic small signal model:
(b) considering channel length modulation :
${r_0\ =\frac {\partial V_{TH}}{\partial I_D}\\ \quad \ \ =\frac{1}{\frac {\partial V_{TH}}{\partial I_D}}\\ \quad \ \ =\frac{1}{\frac{1}{2}\frac{W}{L}\mu_nC_{ox}(V_{GS}-V_T)^2}}\\ { \therefore\ r_0\ =\frac{1}{\lambda I_D}}$
(c) Body Effect :
${g_{m b}=\frac {\partial I_D}{V_{BS}}\ = \frac {W}{L}\mu_n C_{ox}(V_{GS}-V_{Th})(-\frac{\partial V_{Th}}{\partial V_{BS}})\\ We\ \ also\ \ have\ ,\frac{\partial V_{Th}}{\partial V_{BS}}\ =\ -\frac{\partial V_{Th}}{\partial V_{SB}}\ =\ -\frac{\gamma}{2}(2\phi_F+V_{SB})^\frac{-1}{2}\\ Thus\ ,\ g_{mb}\ =g_m\frac{\gamma}{2 \sqrt {2\phi_F+V_{SB}}}\\ \quad \quad \quad \quad \quad \quad \quad=\eta g_m\\ \quad \quad \quad \quad \quad \therefore \eta \ =\frac{g_{mb}}{g_m}}$