What is the poll capacity of the cell?

– Information Rate (Ri) = 12.2 kbps

– Chip Rate (Rc) = 3.84 Mcps

– Required Eb/Nt = 4 dB

– Average interference factor due to other cells = 0.5

– Channel activity Factor = 0.65

– Interference Margin = 3 db

This question appears in Mumbai University > Wireless Networks subject

Marks: 10 M

Load –factor per voice user$\boldsymbol{=(0.6+0.5).\frac{1}{\frac{3840}{12.2}.\frac{1}{2.512}.\frac{1}{0.65}}=0.0057}$

Interference margin=3dB=2=$\frac{1}{1-\rho};\rho=0.5$ $\; \\ \;$

Number of voice users=$\frac{0.5}{0.0057}\approx 87$ per cell