Determine the shear centre as shown in the figure

0

1.3kviews

written 7.1 years ago by

teamques10 ★ 69k

• modified 3.2 years ago

Subject : Structural Analysis 1

Topic : Shear Centre

Difficulty : High

enter image description here

structural analysis

ADD COMMENT EDIT

1 Answer

0

47views

written 7.1 years ago by

teamques10 ★ 69k

• modified 7.0 years ago

enter image description here

$I=I_{XX_1}-I_{XX_2}=\left[ \frac{100\times400^3}{12}\right]-\left[ \frac{(100\times20)(400-2\times20)}{12}\right]\\ I=(533.33\times10^6)-(311.04\times10^6)\\ \underline{I=222.3\times10^6mm^4}$

Distance of shear centre (e)

$e=\frac{h^2b^2t}{4I}=\frac{400^2\times100^2\times20}{4\times22.3\times10^6}=35.98mm\\ \boxed{e=35.98mm}\underline{Ans}$

Create a free account to keep reading this post.

and 4 others joined a min ago.

ADD COMMENT EDIT

Please log in to add an answer.