written 7.1 years ago by | • modified 3.2 years ago |
Question (contd.) carries a load of 80 kN ata n eccentricity of 25mm from the column axis. Take E = 200GPa
Subject : Structural Analysis 1
Topic : Struts
Difficulty : High
written 7.1 years ago by | • modified 3.2 years ago |
Question (contd.) carries a load of 80 kN ata n eccentricity of 25mm from the column axis. Take E = 200GPa
Subject : Structural Analysis 1
Topic : Struts
Difficulty : High
written 7.1 years ago by | • modified 7.0 years ago |
Given data:
D=200mmd=160mmL=6mt=20mmP=80 kNeccentricity e=25mmE=200GPa=2×105MPa
To find: ExtremeStress_
Area of column, A=π4(D2−d2)=π4(2002=1602)A=11309.73mm2_I=π64(D4−d4)=π64(2004−1604)=46.36×106mmz=Iy=46.36×106100=463.6×103mm3
Since the column is fixed at both ends
Leff=L=6000mmLeff=L2=3000mm
Extreme Stresses:_
Maximum bending moment =
p.e. sec(L2√PEI)
Determine the angle L2√PEI
L2√PEI=60002[√80×1032×105×46.38×106]=0.27rad=16∘12′sec16∘12′=1.041
Maximum bending moment
= 80×103×25×1.041=2.08×106 Nmm_
Maximum Compresive stress
σmax=PA+MZ=80×10311309.73+2.08×1064.636×106σmax=7.52 N/mm2_σmin=PA−MZ=80×10311309.73−2.08×1064.636×106σmin=6.62 N/mm2_