Using magnetic boundary condition, show that $\frac{\tan \alpha_{1}}{\tan \alpha_{2}}=\frac{\mu_{r1}}{\mu

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Using magnetic boundary condition, show that $\frac{\tan \alpha_{1}}{\tan \alpha_{2}}=\frac{\mu_{r1}}{\mu_{r2}}$.

written 6.8 years ago by

govindkedar • 280

modified 3.0 years ago by

sagarkolekar ★ 11k

electromagnetic field and wave theory

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