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A simple supported beam shown in fig is subject to a set of 4 concentrated load which moves from left to right, determine a.Absolute max shear force (S.F) b.Absolute max bending moment (B.M)

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1)Absolute Max +ve Shear

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SF=80×1+60×1618+80×1418+100×1118

SF=256.67KN


2) Absolute Max -ve Shear

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SF=[80×1118+60×1318+80×1518+100×1

SF=[258.88]KN


3) Absolute Max B.M.

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ByVarignonstheorem

$80 \times 3+60 \times 5+80 \times 7=320 \times …

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