Subject : Structural Analysis 1

Topic : Cable & Suspension Bridge

Difficulty : Medium

1. Reaction:

∑$M_A$=0

10∗30∗15−$V_B$∗30=0

$V_B$=150KN

∑$F_Y$=0

$V_A$−300+150

$V_A$=150KN

Horizontal thrust

$BMc$=0

$15∗15−H∗3−(10∗15∗{\frac{15}{2}})=0$

H=375KN

2. Maximum and Minimum Tension in the cable

$T_{max}=\sqrt{\left(V_a\right)^2 + \left(H\right)^2}$

$\hspace{1cm}$=$\sqrt{\left(150\right)^2 + \left(375\right)^2}$

$T_{max}=403.9KN$

$T_{min}=H=375KN \\$ $T_{min}=T_c=H=375KN$