written 6.8 years ago by | • modified 2.8 years ago |
Subject : Structural Analysis 1
Topic : General Principles
Difficulty : High
written 6.8 years ago by | • modified 2.8 years ago |
Subject : Structural Analysis 1
Topic : General Principles
Difficulty : High
written 6.8 years ago by | • modified 6.6 years ago |
"In a Linear elastic structure, the displacement of point B of a structure due to unit load acting at point A is equal to the displacement of point A when the unit load is acting at point B."
consider a simply supported beam shown in the figure.
The deflection at b due to load p applied at a.
$\therefore M_{a}=p(M_{a})$ where, $M_{a}$=bending moment due to unit load at 'a'
According to the dummy unit load method, to find the deflection at b apply unit load at b.
Let $m_{b}$ is the bending moment at any section due to unit load at b.
The deflection at b due to load p at 'a'
$q_{ba}=\int_{}^{}\frac{p(m_{a})(m_{b})}{EI}dx \space\space\space\space\space\space --(1)$
The deflection at a due to load p at 'b'
$q_{ab}=\int_{}^{}\frac{p(m_{b})(m_{a})}{EI}dx \space\space\space\space\space\space --(2)$
$\therefore$ From equation (1) and (2), we get
$q_{ab}=q_{ba} \space\space\space\space\space\space --(3)$
The equation (3) doesn't confine to vertical deflection.
Now, consider a general case of a linear elastic system as shown.
Reciprocity of deflections - linear elastic system
$(P)\partial_{BA}=(M)\alpha_{AB} \space\space\space\space\space\space --(4)$
$(n)\partial_{BA}=(n)\alpha_{AB} \space\space\space\space\space\space --(5)$
$\therefore$ Deflection at B due to moment (M=n) at a is equal to the rotation at A due to load (p=n) at B.