0
14kviews
2.5 KW of power is transmitted by an open-belt drive. The linear velocity of belt is 2.5 m/s. The angle of lap on the smaller pulley is 165 deg. The coefficient of friction is 0.3.

Determine the effect on power transmission in the following cases:

i) Initial tension in the belt is increased by 8%

ii) Initial tension in the belt is decreased by 8%

iii) Angle of lap is increased by 8% by the use of an idler pulley, for the same speed and the tension on the tight side, and

iv) Coefficient of friction is increased by 8% by suitable dressing to the friction surface of the belt.

Subject: Kinematics of Machinery

Topic: Belts, Chains and Brakes

Difficulty: High

1 Answer
4
1.2kviews

P= 2.5 kw, μ =0.3, θ =165, ν = 2.5 m/s

P=(T1T2) ν

2500 = (T1T2) ×2.5 or T1T2 =1000N.

T1T2=eμθ=e0.3×165π180=2.37

or T1 = 2.37T2 - T2 =1000 OR T2 =729.9N.

T2 =729.9 ×2.37 = 1729.9 N.

Initial Tension, T0 = …

Create a free account to keep reading this post.

and 4 others joined a min ago.

Please log in to add an answer.