1. To raise the follower through 35 mm during 60 deg rotation of the cam
2. Dwell for next 40 deg of the cam rotation
3. Descending of the follower during the next 90 deg of the cam rotation.
4. Dwell during the rest of cam rotation.

Draw the profile of the cam if the ascending and descending of the cam is with SHM and the line of stroke of the follower is offset 10 mm from the axis of the cam shaft.

What is the maximum velocity and acceleration of the follower during the ascent and the descent if the cam rotates at 150 rpm.

Subject: Kinematics of Machinery

Topic: CAM Mechanism

Difficulty: High

Given h = 35 mm; $\phi_a$= 60$^{\circ}$, N = 150 rpm, $\delta_1$=40 $^{\circ}$ , $r_c$= 25 mm; $\phi_d$= 90$^{\circ}$ , x = 10 mm.

During ascent, $\omega$=$\frac{2\pi\times 150}{60}$= 5$\pi$ rad/s

$v_{max}$= $\frac{h}{2}\times\frac{\pi\omega}{\phi_{a}}$

$v_{max}$= $\frac{35}{2}\times\frac{(\pi\times 5\pi)}{(60\times(\frac{\pi}{180}))}$ = 824.7 mm/s,

$f_{max}$= $\frac{h}{2}\times (\frac{\pi\omega}{\phi_{a}})^{2}$

$f_{max}$= $\frac{35}{2}\times(\frac{(\pi\times 5\pi)}{(60\times(\frac{\pi}{180}))})^{2}$

=38.862 $mm/s^2$ or 38.882 $m/s^2$

$v_{max}$= $\frac{35}{2}\times\frac{(\pi\times 5\pi)}{(90\times(\frac{\pi}{180}))}$ = 549.8 mm/s.

$f_{max}$= $\frac{35}{2}\times(\frac{(\pi\times 5\pi)}{(90\times(\frac{\pi}{180}))})^{2}$

= 17.272 $mm/s^2$ or 17.272 $mm/s^2$