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The Dimensions of The Mechanism As Shown In Fig. Are As Follows. AB=0.45m, BD=1.5m, BC=CE=0.9m.

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The Crank AB Turns Uniformly At 180 rpm. In The Clockwise Direction & The Blocks At D & E Are Working In Frictionless Guides. Draw The Velocity Diagram For The Mechanism & Find The Velocities Of The Sliders D & E In Their Guides. Also Determine The Turning Moment At A If a Force Of 500N. Acts On D In The Direction Of Arrow X & a Force Of 750N. On E In The Direction Of Arrow Y.


Subject: Kinematics of Machinery

Topic: Velocity Analysis of Mechanism (Mechanism up-to 6 links)

Difficulty: High

1 Answer
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Given: NBA = 180 rpm. or ωBA = 2π×18060=18.85 rad/s

Since AB= 0.45m, therefore velocity of B with respect to A or velocity of B (because A is a fixed point)

vBA=vB=ωBA×AB=18.85×0.45=8.5m/s

Velocities of the sliders D and E

First of all the space diagram …

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