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Find the new dimensions and increase in discharge.


A rectangular channel 4m wide has depth of water1.5m. The slope of the bed of channel is 1 in 1000. C=55. It is desired to increase the discharge keeping i & C constant.Find the new dimensions and increase in discharge.

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Given,

  • b = 4m
  • d = 1.5m

  • i = 11000

  • C = 55

i.e.Area=bd=41.5=6m2


Wetted Perimeter,P=d+b+D=1.5+4+1.5=7m

m=AP=47=0.857

Q=ACmi=6550.85711000=9.66m3/s


For max discharge for a given area, slope of bed and roughness.

Let,

b1=new width of channel

d1=new depth of flow

Area,A=b1d1, where A=6m2

B=b1d1



Max discharge, b1=2d1

6=2d1d1

i.e.d12=62=3

i.e.d1=3=1.732

b1=21.732=3.464


New dimension, b1=3.464m and d1=1.732m


Wetted Perimeter,p1=d1+b61+d1=1.732+3.464+1.732=6.928


Hydraulic mean depth,m1=AP1=66.928=0.866m

[m1=d12=1.732=0.866m]


Max discharge,, Q1=ACm1i=6550.86611000=9.71m3/s


Increase in discharge,, Q1Q=9.719.66=0.05m3/s Ans.

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