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Calculate the discharge in each pipe of the network shown in figure below by Hardy-cross method. Take n=2

Subject: Fluid Mechanics 2

Topic: Flow Through Pipes

Difficulty: High

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1 Answer
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Solution :

Required Formulae

$h_f=\sum rQ_o^2$

and

$\begin{aligned}\therefore \Delta Q=-\frac{\sum rQ_o^n}{\sum nrQ_o^{n-1}} \end{aligned}$

For n = 2

$\begin{aligned}\therefore \Delta Q=-\frac{\sum rQ_o^2}{\sum nrQ_o^{2}} \end{aligned}$

Consider the assumed flow rate

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We have to follow the iterative method upto the $\Delta Q$ becomes negligible,

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From 4th iteration we get corrected flow in each pipe , we can also follow further iteration upto very very small for $\Delta Q$

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Let me know if something is wrong.


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