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Calculate RIs of core & cladding material of a fiber that has NA = 0.20 & fractional change in RI as 1%.

written 6.9 years ago by neeta.vanage • 870

modified 2.8 years ago by pedsangini276 • 4.8k

Subject: Applied Physics 2

Topic: Fiber Optics

Difficulty: Medium

engineering physics

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1 Answer

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written 6.8 years ago by neeta.vanage • 870

modified 6.8 years ago by saurabhsingh • 40

$ n_1 = ? ,$

$ n_2 = ? , $

$ NA = 0.20\\ \text{ fractional index change Δ = 1 %= 1/100 = 0.01 } \\ NA = n_1 \\ 0.20 = n_1 \\ 0.20 = n_1 \\ n_1 = 1.4285 \\ NA =(n_1)^2 - (n_2)^2 \\ (0.20)^2 = (1.4285)^2 - (n_2 )^2 \\ n_2 = 1.414\\ $

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