Calculate RIs of core & cladding material of a fiber that has NA = 0.20 & fractional change in RI as 1%.

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written 7.2 years ago by

neeta.vanage • 880

modified 3.2 years ago by

pedsangini276 • 4.8k

Subject: Applied Physics 2

Topic: Fiber Optics

Difficulty: Medium

engineering physics

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1 Answer

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written 7.1 years ago by

neeta.vanage • 880

modified 7.1 years ago by

saurabhsingh • 40

$n_1 = ? ,$

$n_2 = ? ,$

$ NA = 0.20\\ \text{ fractional index change Δ = 1 %= 1/100 = 0.01 } \\ NA = n_1 \\ 0.20 = n_1 \\ 0.20 = n_1 \\ n_1 = 1.4285 \\ NA =(n_1)^2 - (n_2)^2 \\ (0.20)^2 …

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