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Calculate the numerical aperture (NA) & hence the acceptance angle for an optical fiber given that RIs of core & cladding are 1.45 & 1.40 respectively.

written 7.0 years ago by neeta.vanage • 880

modified 2.9 years ago by pedsangini276 • 4.8k

Subject: Applied Physics 2

Topic: Fiber Optics

Difficulty: Medium

engineering physics

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1 Answer

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written 6.9 years ago by neeta.vanage • 880

modified 6.9 years ago by saurabhsingh • 40

$ n_1 = 1.45 \ n_2 = 1.40\ NA=0.377 Sin i_m = NA\ ⸫ i_m = sin - ( NA) \ i_m = sin - ( 0.377)\ i_m = 22.19° \ $

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