0
1.0kviews
Newtons rings are observed in the reflected light of λ=6000˚A Find the thickness of the air film corresponding to the 10th dark ring.

Subject: Applied Physics 2

Topic: Interference And Diffraction

Difficulty: Medium

1 Answer
0
8views

λ = 6000 x108 cm, n=10

For dark ring , 2μt= nλ

Thickness t= \frac{nλ}{2μ}

For air film μ=1,

\therefore Thickness t= \frac{nλ}{2} = \frac{10 \times 6000 \times 10^{-8}}{2} = 30000 \ AU

Create a free account to keep reading this post.

and 5 others joined a min ago.

Please log in to add an answer.