written 7.2 years ago by | • modified 6.9 years ago |
Subject :- Machine Design -I
Topic :- Spring
Difficulty :- Medium
written 7.2 years ago by | • modified 6.9 years ago |
Subject :- Machine Design -I
Topic :- Spring
Difficulty :- Medium
written 6.9 years ago by | • modified 6.9 years ago |
D=Meandiameterofthespringcoil
d=diameterofthespringwire
n=Numberofactivecoils
G=modulusofrigidityforthespringmaterial
W=axialloadonthespring
C=Springindex=D/d
p=pitchofthecoils
δ=deflectionofthespringasaresultofanaxialloadW
Totalactivelengthofthewire,
l=lengthofonecoil∗no.ofactivecoils=πDn
Letθ=angulardeflectionofthewirewhenacteduponbythetorqueT
Axialdeflectionofthespring,
δ=θ∗D2.....eqn.1
Also,
TJ=τD/2=GθI
θ=TIJG
J=Polarmomentofinertiaofspringwire
θ=TIGJ=W∗D2∗πDnπ32∗d4G....eqn.2
Substitutingthisvalueineqn.1
δ=16WD2nGd4∗D2=8WD3nGd4=8WC3nGd
andthestiffnessofthespringorspringrate,
Wδ=Gd48D3n=Gd8C3n=constant