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With neat sketches for failure cross section areas check all components under different failures.

A knuckle joint is to be design to connect two mild steel bars under a tensile load of 150 KN. The allowable stresses are 75Mpa in tension, 50Mpa in shear and 150 Mpa in crushing. (Assume empirical relations as Diameter of knuckle pind1=d , Outer diameter of eye d2=2d, diameter of knuckle pin head and collar d3=1.5d, thickness of single eye t = 1.25d, thickness of fork t1=0.75d, thickness of pin head t2=0.5d)

  1. Draw neat sketch of knuckle joint.
  2. Find the diameter of the rod (d).
  3. Using empirical find all dimensions.
  4. With neat sketches for failure cross section areas check all components under different failures.

Subject: Machine Design -I

Topic: Design against static Loads, Bolted and welded joints under eccentric loading. Power Screw

Difficulty: Medium

1 Answer
1
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  1. Draw a neat sketch of knuckle joint:

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  1. FInd the diameter of the rod(d):

d=4Pσtπ=4(150103)π75=50.462or52mm

  1. Using empirical find all dimensions:

Diameter of knuckle pin:

d1=d=52mm

Outer diameter of eye:

d2=2d=104mm

Diameter of knuckle pin head and collar:

d3=1.5d=78mm

Thickness of single eye:

t=1.25d=656mm

Thickness of fork:

t1=0.75d=39mm

Thickness of pin head:

t2=0.5d=26mm

  1. Check for components under different failures:

Stresses in single eye/eye:

Tensile stress:

σt=pt(d2d)=44.37MPa

Crushing stress:

σc=ptd=44.37MPa

Shear stress:

τ=pt(d2d)=44.37MPa

Stresses in double eye/fork:

Tensile stress:

τt=p2t1(d2d)=36.98MPa

Crushing stress:

σc=p2t1d=36.98MPa

Shear stress:

τ=p2t1(d2d)=36.98MPa

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