Subject:- Applied Chemistry 2.

Topic:- Green Chemistry

Difficulty:- Medium

a) $C_6H_6 + 4.5 O_2 \rightarrow C_4H_4O_3 + 2CO_2 + 2H_2O$

b) $CH_3CH=CH_2 + H2 \rightarrow CH_3CH_2CH_3$

c)$ C_6H_6 + CH_3Cl \rightarrow C_6H_5CH_3 + HCl$

a) C6H6 + 4.5 O2 C4H4O3 + 2CO2 + 2H2O Solution: molecular weight of benzene C6 H6 = 78 Molecular weight of 4.5O2 = 144 Molecular weight of C4H2O3 = 98 % Atom economy = Molecular weight of desired product/ Sum of the molecular weight of desired product x 100 = 98/78 +144 x 100 % Atom economy = 44.144

b) CH3CH=CH2 + H2 CH3CH2CH3

Solution: Molecular weight of CH3CH=CH2 = 42 Molecular weight of H2 = 2 Molecular weight of CH3CH2CH3 = 44 % Atom economy = Molecular weight of desired product/ Sum of the molecular weight of desired product x 100 44/42 +2 X100 % Atom economy = 100

c) C6H6 + CH3Cl C6H5CH3 + HCl Solution: molecular weight of benzene C6 H6 = 78 Molecular weight of CH3Cl = 50.5 Molecular weight of C6H5CH3 = 92 = 92 / 78 + 50.5 X 100 = 92/ 128.5 % Atom economy = 71.5