written 6.9 years ago by | modified 2.8 years ago by |
Subject :- Applied Physics 2.
Topic :- Laser.
Difficulty :- Medium.
written 6.9 years ago by | modified 2.8 years ago by |
Subject :- Applied Physics 2.
Topic :- Laser.
Difficulty :- Medium.
written 6.8 years ago by |
Ampere’s Circuital law states that “the line integral of magnetic field intensity H around a closed path is exactly equal to the direct current enclosed by that path.” The mathematical representation of Ampere’s law is
$$\vec{H}.{dl}=I \tag{1}$$
The law is very useful to determine $\vec{H}$ when the current distribution is symmetrical.
Since, $\vec{B}=\mu\vec{H}$
Equation (1) can be written as $$\oint\vec{B}.{dl}=\mu_0I$$
This is called the integral form of Ampere’s circuital law
Replacing $ I=\int_S\vec{J}.\vec{ds}$ where $\vec{J}$ is current density and $S$ is the surface area bounded by the path of integration of $\vec{H}$, we can write $$\oint\vec{H}.\vec{dl}=\int_S\vec{J}.\vec{ds}$$
Using stokes theorem, this can be written as
$$\oint_S(\vec{\nabla}\times\vec{H}.\vec{ds}=\int_S\vec{J}.\vec{ds}$$
Hence, $\vec{\nabla}\times\vec{H}=\vec{J}$
Since,$\vec{B}=\mu_0\vec{H}$ in free space, we can write
$$ \vec{\nabla}\times\vec{B}=\mu_0\vec{J}$$
This is called the differential or point form of ampere’s circuital law.