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Determine optimum time cost combination.

The details of activities are given below:

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Assuming indirect cost as Rs. 1000/- day, determine optimum time – cost combination.

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Cost Slope=Crash Cost - Normal CostNormalTimeCrashTime

Stage 1 : - All Normal

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Critical path = 10-30-60-70

Project duration = 15 days

Stage 2 : - All Crash

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Critical path = 10-30-60-70

Project duration = 8 days

Stage 3 : - All Normal + Crash E by 3 days

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Critical path = 10-30-60-70 / D-E-F

Project duration = 12 days

Stage 4 : - Stage 3 + Crash D by 2 days

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Critical path = 10-20-50-70 / A-B-G

10-30-60-70 / D-E-F

Stage Description Duration Direct Indirect Addition Total
1 All Normal 15 47000 15×1000=15000 - 62000
2 All Crash 8 76000 8×1000=8000 - 84000
3 All Normal + Crash E by 3 days 12 47000 12×1000=12000 3×1000=3000 62000
4 Stage 3 + Crash D by 2 days 10 47000 10×1000=10000 3000+2×1500 63000

Optimum cost = Rs. 62000/-

Optimum duration = 12 days

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