Determine optimum cost & estimated as Rs. 5000/- day.

Activity	Normal Duration (days)	Normal Cost (Rs.)	Crash Duration (days)	Crash Cost (Rs.)
1-2	6	7000	3	14500
1-3	8	4000	5	8500
2-3	4	6000	1	9000
2-4	5	8000	3	15000
3-4	5	5000	3	11000
4-5	7	8000	4	15000

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written 6.9 years ago by

teamques10 ★ 68k

Activity	Normal Duration (days)	Normal Cost (Rs.)	Crash Duration (days)	Crash Cost (Rs.)	Cost Slope
1-2	6	7000	3	14500	2500
1-3	8	4000	5	8500	1500
2-3	4	6000	1	9000	1000
2-4	5	8000	3	15000	3500
3-4	5	5000	3	11000	3000
4-5	7	8000	4	15000	2333.33
			38000	73000

$\text{Cost Slope} = \frac{\text{Crash Cost - Normal Cost}}{\text{Normal Time - Crash Time}}$

Stage 1 : - Normal Time

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Critical path = 1-2-3-4-5

Project duration = 22 days

Stage 2 :- Crash Time

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Critical path = 1-3-4-5

Project duration = 12 days

Stage 3 :- Stage 1+ Crash C by 2 days and Crash E by 1 day

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Critical path =1-2-3-4-5 = 1-3-4-5

Project duration = 19 days

Stage 4 :- Stage 3 +Crash A by 1 day & Crash B by 1 day

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Critical path = 1-2-3-4-5 = 1-3-4-5

Project duration = 18 days

Stage	Description	Duration	Direct	Indirect	Addition	Total
1	All Normal	22	38000	22,5000=11000	-	148000/-
2	All Crash	12	73000	12,5000=60000	-	133000/-
3	Stage 1+ Crash C by 2 days and Crash E by 1 day	19	38000	19,5000=95000	2,1000+1,3000	138000/-
4	Stage 3 +Crash A by 1 day & Crash B by 1 day	18	38000	18,5000=90000	5000+1,2500+1,2500	137000/-

∴ Optimum cost = Rs. 137000/-

Optimum duration = 18 days

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