0
3.2kviews
Design self bias circuit using JFET for midpoint biasing. Let IDSS=8mA,Vp=3V
1 Answer
0
46views

Step 1: Circuit Diagram

enter image description here

Step 2: Finding IDSQandVGSQ

Since mid-point biasing is mentioned then,

IDSQ=12IDSS=12×8mA

IDSQ=4mA

We know that,

IDSQ=IDSS(1VGSQVP)2

4mA=8mA(1+VGSQ3)2

VGSQ=0.87V

Step 3: Finding Rs

VGS=IDSQ×Rs

0.87=4mA×Rs

Rs=217.5Ω

Step 4: Finding Rd

Apply KVL from VDD to Ground,

VDDIDSQ(Rd+Rs)VDSQ=0

Since mid point biasing is …

Create a free account to keep reading this post.

and 4 others joined a min ago.

Please log in to add an answer.