Design voltage divider biased circuit to give Icq=5mA, VCEq=5V and $\beta$=100.

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Design voltage divider biased circuit to give Icq=5mA, VCEq=5V and

$\beta$ =100.

written 7.3 years ago by

teamques10 ★ 69k

modified 2.5 years ago by

yashbeer ★ 11k

discrete electronics

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written 7.3 years ago by

teamques10 ★ 69k

Step 1: Circuit Diagram

Step 2: Finding Vcc

$Vcc = 2V_{CEQ}$

Vcc = 10V

Step 3: Finding RE

$V_{RE} = 10% of Vcc$

$V_{RE} = 1V$

We know that,

$V_{RE} = I_ER_E$

Finding $I_E,$

$I_C= \beta I_B$

$I_B = I_C/\beta = 5mA/100 ………………..Ic=5mA(Given)$

$I_B= 50\mu A$

$I_E = I_B+I_C$

$I_E …

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