written 6.9 years ago by | modified 2.8 years ago by |
Mumbai University > Electronics Engineering > Sem 4 > Discrete Electronic Circuits
Marks: 5M
written 6.9 years ago by | modified 2.8 years ago by |
Mumbai University > Electronics Engineering > Sem 4 > Discrete Electronic Circuits
Marks: 5M
written 6.9 years ago by |
Figure 1 shows the clipper circuit diagram, Figure 2 shows the input waveform and Figure 3 shows the output waveform.
When Vin=0, diode is forward biased Vo=1.5V
During positive half cycle of ac input signal.
i. When Vin< 1.5V, diode is forward biased.
Vin+1.5V=Vo, i.e. Vo=0+1.5V=1.5V. As shown in Figure 3.
ii. When Vin> 1.5V, diode is forward biased.
Vin+1.5V=Vo, i.e. Vo=3V+1.5V=4.5V. As shown in Figure 3.
During negative half cycle of ac input signal.
i. When Vin<1.5V, diode is forward biased.
Vin+1.5V=Vo, i.e. Vo=-1+1.5V=0.5V. As shown in Figure 3.
ii. When Vin>1.5V, diode is reversed biased.
Vo=0V. As shown in Figure 3.
4) This type of clipper is called as biased series clipper where a dc voltage is applied to clip the waveform in positive or negative half cycle.