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Determine the variance of the project

Mumbai University > Civil Engineering > SEM 8 > Construction Management

Marks: 10M

Following is the data of associated with PERT project

Activity A B C D E F G
Preceding Activity -- -- A B A B C,D
to 6 5 4 4 4 2 4
tm 9 8 7 7 7 5 10
tp 12 17 22 16 10 8 22
Z -3 -2 -1 0 1 2 3
P% 0.13 2.28 15.87 50 84.13 97.72 99.87

i) Determine the variance of the project

ii) What is the probability of completing the project in 29 days?

iii) What is the schedule duration with 90% probability?

1 Answer
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Activity Preceding Activity to tm tp te σ σ2
A -- 6 9 12 9 1 1
B -- 5 8 17 9 2 4
C A 4 7 22 9 3 9
D B 4 7 16 8 2 4
E A 4 7 10 7 1 1
F B 2 5 8 5 1 1
G C,D 4 10 22 11 3 9

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  1. Project Duration: 29 Days

    Critical path: 10-20-40-50 i.e. A-C-G

  2. Probability of completing project in 29 days:

    $T_s$: Scheduled completion time

    $T_E$: Estimated Time of completion

    $z =\frac{T_s- T_E}{\sigma} = \frac{T_s - T_E}{\sqrt{\sigma^2}}$

$\sqrt{\sigma^2} = \sqrt{\text{Sum of variance of critical path}}=\sqrt{19}=4.35$

Z = 0

P% for corresponding Z value = 50%

Therefore, Probability of completing project in 29 days is 50%.

  1. What is the schedule duration with 90% probability?
Z -3 -2 -1 0 1 2 3
P% 0.13 2.28 15.87 50 84.13 97.72 99.87

For 90% probability:

$\frac{(0.977 - 0.841)}{(2 - 1)} = \frac{(0.977 - 0.90)}{(2 - x)}$

X= 1.43

Therefore,

$z=1.43= \frac{T_s - T_E}{\sigma}$

$1.43 = \frac{T_s- 29}{4.35}$

$T_s= 35.2205 \text{Days}$

Schedule duration with 90% probability is 35.220 Days.

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