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A turbine is to operate under a head of 20 m at 200 rpm. The discharge is 9 cumec. If the efficiency is 90%,Determine the performance of the turnbine under a head of 20m

Mumbai University > Electronics and telecommunication > Sem 7 > Applied Hydraulics

Marks: 08

Years: MAY 2016

1 Answer
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Head on turbine H1=20m

Speed N1=200r.p.m

Discharge Q1=9m3/s

Overall efficiency No=90% or 0.90

Performance of the turbine under a head H2=20m means to find the speed discharge and power developed by the turbine when working under the head of 20 m

Let for the head H2=20m

Speed =N2

discharge Q2

Power P2

Using the relation

No=PW.P=P1p×g×Q1×H11000P1=No×p×g×Q1×H11000=0.90×1000×9.81×9×201000=1589.22KwN1H1=N2H2N2=N1H2H1=200×2020=200r.p.mAlsoQ1H1=Q2H2Q2=Q1×H2H1=9×2020=9m3/s

And P1H3/21=P2H3/22P2=P1H3/22H3/21=P1(H2H1)3/2=1589.22(2020)3/2=1589.22Kw

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